(4x^2-21x-5)(x-4)=

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Solution for (4x^2-21x-5)(x-4)= equation: 


Simplifying
(4x2 + -21x + -5)(x + -4) = 0

Reorder the terms:
(-5 + -21x + 4x2)(x + -4) = 0

Reorder the terms:
(-5 + -21x + 4x2)(-4 + x) = 0

Multiply (-5 + -21x + 4x2) * (-4 + x)
(-5(-4 + x) + -21x * (-4 + x) + 4x2 * (-4 + x)) = 0
((-4 * -5 + x * -5) + -21x * (-4 + x) + 4x2 * (-4 + x)) = 0
((20 + -5x) + -21x * (-4 + x) + 4x2 * (-4 + x)) = 0
(20 + -5x + (-4 * -21x + x * -21x) + 4x2 * (-4 + x)) = 0
(20 + -5x + (84x + -21x2) + 4x2 * (-4 + x)) = 0
(20 + -5x + 84x + -21x2 + (-4 * 4x2 + x * 4x2)) = 0
(20 + -5x + 84x + -21x2 + (-16x2 + 4x3)) = 0

Combine like terms: -5x + 84x = 79x
(20 + 79x + -21x2 + -16x2 + 4x3) = 0

Combine like terms: -21x2 + -16x2 = -37x2
(20 + 79x + -37x2 + 4x3) = 0

Solving
20 + 79x + -37x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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